# How do you graph #y=4x+3# using a table?

##### 1 Answer

Well, think of it this way: you plug in something for

This equation is **linear**:

where

#m# is the slope (change in y over change in x) and#b# is the y-intercept (where it hits the#y# axis).

Your equation just has

So, let's make a quick table. You need at least two points to make a straight line, and three points to make a curve. Let's do five points though for practice.

#x = -2 -> y = 4(-2) + 3 = -5#

#x = -1 -> y = 4(-1) + 3 = -1#

#x = 0 -> y = 4(0) + 3 = 3#

#x = 1 -> y = 4(1) + 3 = 7#

#x = 2 -> y = 4(2) + 3 = 11#

In a table it then looks like this:

#color(white)([(color(black)(ul(y)),color(black)(ul("|")),color(black)(ul(x))),(color(black)(-5),color(black)(|),color(black)(-2)),(color(black)(-1),color(black)(|),color(black)(-1)),(color(black)(3),color(black)(|),color(black)(0)),(color(black)(7),color(black)(|),color(black)(1)),(color(black)(11),color(black)(|),color(black)(2))])#

And after plotting each point by looking at

graph{4x + 3 [-2, 2, -5, 11]}

If you look on this graph, you should be able to find every point we had on the table.