How do you graph #y=-5cos(1/2)x#?

1 Answer
May 19, 2018

Answer:

You have an inverted graph of cosine with a vertical stretch factor of 5 was a horizontal stretch factor of 2, it has no shift.

Explanation:

I assume you mean:

#y = − 5 cos ( 1/ 2 x)#

if so standard form is:

#acos(bx -c) + d#

#a = "amplitude (vertical stretch)"#
#b = "horizontal stretch"#
#c = "horizontal shift"#
#d = "vertical shift"#

if #a <0# graph is inverted.

so you have an inverted graph of cosine with a vertical stretch factor of 5 was a horizontal stretch factor of 2, it has no shift.
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