How do you graph #y=5x-1#?

Question

5806 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-27T23:12:20

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#y = (5 * 0) - 1#

#y = 0 - 1#

#y = -1# or #(0, -1)#

Second Point: For #x = 1#

#y = (5 * 1) - 1#

#y = 5 - 1#

#y = 4# or #(1, 4)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+1)^2-0.035)((x-1)^2+(y-4)^2-0.035)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y - 5x + 1)(x^2+(y+1)^2-0.035)((x-1)^2+(y-4)^2-0.035)=0 [-10, 10, -5, 5]}