# How do you graph #y=arccos(x/3)#?

##### 1 Answer

Instead of y-explicit form y = arccos (x/3), use the inverse x-explicit form x = 3 cos y. See the graphs and the explanation

#### Explanation:

I reiterate that the graphs of locally bijective y = f(x) and its inverse

The inverse of

For that matter, the same

bijective

and

This waveform twines about y-axis. The amplitude (max

is 3 units and the period ( from the inverse x = 3 cos y) is

Data for making one half wave tor

The other half wave is obtained by twining this beyond, for #y in

[pi, 2pi]], around y-axis.

Observe that #abs x <= 1 (amplitude).

Graph of

graph{x-3 cos y = 0 [-3.14 3.14 0 3.14]}

Extended graph for

graph{x-3 cos y = 0 [ -50 50 -25 25]}

The graphs are on uniform scale.