How do you graph #y = arctan 4x#?

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Answer 1 · 2018-08-13T12:41:35

See #oo-arm# single wave.

arctan values #in ( - pi/2, pi/2 )#

#y = arctan ( 4 x ) ne# ( zeros of cos y ) # +-pi/2#.

Asymptotes: #y = +- pi/2#

Period for x:: # pi/4#

See graph, depicting all these aspects.

graph{(y-arctan(4x))(y-pi/2)(y+pi/2)=0}.

Wholesome #oo#-arm waves #uarr darr#, using the inverse

#x = 1/4 tan y#.

graph{4x-tan y = 0[-20 20 -10 10] }.