How do you graph $y = arctan 4x$ ?

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Answer 1 · 2018-08-13T12:41:35

See $oo-arm$ single wave.

arctan values $in ( - pi/2, pi/2 )$

$y = arctan ( 4 x ) ne$ ( zeros of cos y ) $+-pi/2$ .

Asymptotes: $y = +- pi/2$

Period for x:: $pi/4$

See graph, depicting all these aspects.

graph{(y-arctan(4x))(y-pi/2)(y+pi/2)=0}.

Wholesome $oo$ -arm waves $uarr darr$ , using the inverse

$x = 1/4 tan y$ .

graph{4x-tan y = 0[-20 20 -10 10] }.

How do you graph y = arctan 4xy = arctan 4x?