How do you graph y = arctan 4x?

1 Answer
Aug 13, 2018

See oo-arm single wave.

Explanation:

arctan values in ( - pi/2, pi/2 )

y = arctan ( 4 x ) ne ( zeros of cos y ) +-pi/2.

Asymptotes: y = +- pi/2

Period for x:: pi/4

See graph, depicting all these aspects.

graph{(y-arctan(4x))(y-pi/2)(y+pi/2)=0}.

Wholesome oo-arm waves uarr darr, using the inverse

x = 1/4 tan y.

graph{4x-tan y = 0[-20 20 -10 10] }.