How do you graph $y=cos(4x)$ ?

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Answer 1 · 2018-06-07T07:09:17

As below.

$y = cos (4x)$

Standard form is $y = A cos (Bx - C) + D$

$A = 1, B = 4, C = D = 0$

$Amplitude = |A| = 1$

$"Period " = (2pi) / |B| = (2pi) / 4 = pi/2$

$"phase Shift " = -C / B = 0$

$"Vertical Shift " = D = 0$

graph{cos (4x) [-10, 10, -5, 5]}

How do you graph y=cos(4x)y=cos(4x)?