How do you graph #y = cos (pi /2) x#?

1 Answer
Sep 5, 2015

Answer:

The graph looks like:

graph{cos(pi/2*x) [-1.004, 6.79, -1.715, 2.18]}

Explanation:

When you draw a graph of a function #f(x)=cosax#, the amplitude remains unchanged (#<-1;1>#), but the period changes to #T=(2pi)/a#. In this case the period is #4#