How do you graph #y=cos2x+4#?

1 Answer
Mar 3, 2018

Answer:

See below.

Explanation:

Assuming there are no omitted parentheses in the question, this ia

#y = cos(2x)+4#

Replacing argument #x# with #bx# changes the period from #2pi# to #2pi/b#, in this case the period will be #pi#

Adding a constant #d# after the cosine moved the graph up (for positive #d#) or down (for negative #d#). In this case we shift the graph up #4#.

graph{cos(2x)+4 [-6.45, 6.034, 0.9, 7.144]}