Question

How do you graph `y= (cosx)/x`?

Answer 1

there's no direct approach (as far as I know)

Explanation:

we have `cosx1/x`
plot `cosx` graph{cosx [-10, 10, -5, 5]}
now plot`1/x`
graph{1/x [-10, 10, -5, 5]}

`cosx/x` is hybrid of both
notice `cosx` is an even function and 1/x is an odd function
and resultant function is an odd function
graph{(cosx)/x [-12.66, 12.65, -6.33, 6.33]}

similarly `sinx/x`
graph{sinx/x [-12.66, 12.65, -6.33, 6.33]}
it looks different because sinx and 1/x are both odd(graph is symmetrical) because resultant function becomes even