# How do you graph #y= (cosx)/x#?

##### 1 Answer

Jun 10, 2018

there's no direct approach (as far as I know)

#### Explanation:

we have

plot

now plot

graph{1/x [-10, 10, -5, 5]}

notice

and resultant function is an odd function

graph{(cosx)/x [-12.66, 12.65, -6.33, 6.33]}

similarly

graph{sinx/x [-12.66, 12.65, -6.33, 6.33]}

it looks different because sinx and 1/x are both odd(graph is symmetrical) because resultant function becomes even