How do you graph #y=sin2x#?

1 Answer
Aug 9, 2018

Below

Explanation:

When written in the form #y=asin(nx+b)+c# where
#a# is the amplitude
#n# is used to find the period of the function
#b# is to find the shift to the left or right by #b# units
#c# is to find the shift upwards or downwards by #c# units

Looking at #y=sin2x#, it is clear that:
#a=1#
#b=0#
#"period"=(2pi)/n=(2pi)/2=pi#
#c=0#

Therefore, #y=sin2x# is basically the #y=sinx# graph but instead of having a period of #2pi#, it has a period of #pi#. So what that means is that in #y=sin2x#, you will see two #sinx# graphs occurring.

graph{sin(2x) [-10, 10, -5, 5]}