How do you graph #y=-sin2x#?

1 Answer
Jul 13, 2018

Answer:

As below

Explanation:

Standard form of sine function is #y = A cos (Bx - C) + D#

#y = - sin 2x#

#A = -1, B = 2, C = 0, D = 0#

#Amplitude = |A| = 1#

Period #= (2 pi)/ |B| = (2 pi)/ 2 = pi#

Phase shift # = -C / B = 0#

Vertical Shift #= D = 0#

graph{-sin (2x) [-10, 10, -5, 5]}