Question

How do you graph `y=sin2x+1`?

Answer 1

graph{sin(2x)+1 [-10, 10, -5, 5]}

Explanation:

The amplitude of `y=sin(2x)+1` is 1 because there is no other co-efficient present in front of the function.

We know that the original graph is `y=sin(x)`

graph{ y= sin(x) [-10, 10, -5, 5]}

We are dilating the graph by a factor of `1/2` from the y axis
Therefore every x value is halved and the graph is

graph{sin(2x) [-10, 10, -5, 5]}

There is a translation of 1 unit to the positive direction of the y -axis, therefore we shift the entire graph up 1 unit.

graph{sin(2x)+1 [-10, 10, -5, 5]}

And there you have it, the graph of `y=sin(2x)+1`