Question

How do you graph `y=sin3(x+pi/3)`?

Answer 1

Graph is inserted. Observe period `2/3pi`, choosing `x in [0, 2/3pi]`, for one period. y ranges between `+-(amplitude}=+-1`, between the ends `[0, 0] and [2/3pi, 0]`.

Explanation:

`y = sin (3x+pi)=-sin (3x)`

The graph is inserted.

The period of this sine wave is `(2pi)/3`.

The amplitude is 1.

Sample period: `x in [0, 2/3pi]`

Ends for this full wave: `(0, 0) and (2/3pi, 0)`

graph{y+sin (3x)=0x^2 [-10, 10, -5, 5]}