How do you graph #y=sin3(x+pi/3)#?

1 Answer
Nov 18, 2016

Answer:

Graph is inserted. Observe period #2/3pi#, choosing #x in [0, 2/3pi]#, for one period. y ranges between #+-(amplitude}=+-1#, between the ends #[0, 0] and [2/3pi, 0]#.

Explanation:

# y = sin (3x+pi)=-sin (3x)#

The graph is inserted.

The period of this sine wave is #(2pi)/3#.

The amplitude is 1.

Sample period: #x in [0, 2/3pi]#

Ends for this full wave: #(0, 0) and (2/3pi, 0)#

graph{y+sin (3x)=0x^2 [-10, 10, -5, 5]}