How do you graph #y=x+9#?

1 Answer
Apr 1, 2016

Recognize the equation as a straight line;
find two coordinates that satisfy the equation and plot them on a graph;
draw a straight line through those points.

Explanation:

Two simple coordinates for #y=x+9# would be the intercepts:
#color(white)("XXX")(0,9) and (-9,0)#

Plotting these point and drawing a line through them:
graph{(x^2+(y-9)^2-0.02)((x+9)^2+y^2-0.02)(x-y+9)=0 [-12.31, 13, -1.91, 10.75]}