# How do you identify all asymptotes or holes for #f(x)=(2x-2)/(x^2-2x-3)#?

##### 1 Answer

Nov 24, 2016

The vertical asymptotes are

No slant asymptote

The horizontal asymptote is

No holes

#### Explanation:

Let's factorise the denominator

The domain of

As you cannot divide by

The vertical asymptotes are

The degree of the numerator

We calculate the limits of

The horizontal asymptote is

graph{(2x-2)/(x^2-2x-3) [-8.89, 8.89, -4.444, 4.445]}