# How do you identify all horizontal and slant asymptote for #f(x)=4/(x-2)^3#?

##### 1 Answer

Nov 7, 2016

#### Answer:

The vertical asymptote is

The horizontal asymptote is

#### Explanation:

As you cannot divide by

There is no slant asymptote as the degree of the numerator is smaller than the degree of the denominator.

So there is a horizontal asymptote

graph{4/(x-2)^3 [-16.02, 16.01, -8.01, 8.01]}