# How do you identify all vertical asymptotes for #f(x)=(x^2-5x+4)/(x^2-4)#?

##### 2 Answers

Aug 9, 2017

#### Answer:

**Vertical asymptotes are at**

#### Explanation:

For vertical asymptotes to form denominator is zero.

So vertical asymptotes are at

graph{(x^2-5x+4)/(x^2-4) [-40, 40, -20, 20]} [Ans]

Aug 9, 2017

#### Answer:

#### Explanation:

The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the values that x cannot be and if the numerator is non-zero for these values then they are vertical asymptotes.

#"solve "x^2-4=0rArr(x-2)(x+2)=0#

#rArrx=+-2" are the asymptotes"#

graph{(x^2-5x+4)/(x^2-4) [-10, 10, -5, 5]}