# How do you identify the 10th term of the sequence 2, -8, 32?

Dec 12, 2017

$- 524288$

#### Explanation:

$2 , - 8 , 32 , . .$

$\frac{32}{- 8} = \frac{- 8}{2} = - 4$

so we have a GP common ratio $r = - 4$

for a GP the nth term

$n t h = a {r}^{n - 1}$

$10 t h = 2 {\left(- 4\right)}^{9}$

$= - 524288$