# How do you identify the center and radius of the circle (x-1)^2+y^2=10?

Apr 7, 2018

Center: $\left(1 , 0\right)$ Radius: $\sqrt{10}$

#### Explanation:

The standard equation of a circle with center $\left(h , k\right)$ and radius $r$ is

${\left(x - h\right)}^{2} + {\left(y - k\right)}^{2} = {r}^{2}$

Examining

${\left(x - 1\right)}^{2} + {y}^{2} = 10 ,$

we see we really just have

${\left(x - 1\right)}^{2} + {\left(y - 0\right)}^{2} = {10}^{2}$, making the center

$\left(1 , 0\right)$ and the radius ${r}^{2} = 10 \to r = \sqrt{10}$