Question

How do you identify the center and radius of the circle `(x+3)^2+(y-8)^2=16`?

Answer 1

center:`(-3, 8); " radius "= 4`

Explanation:

Given: `(x + 3)^2 + (y - 8)^2 = 16`

The standard form of a circle `(x -h)^2 + (y-k)^2 = r^2`, where center is `(h, k)` and `r` = radius.

From the given equation `(x - - 3)^2 + (y - 8)^2 = 16` to get a positive value, there must be a negative.

This means the center is `(-3, 8)`

Radius `= sqrt(16) = 4`