# How do you identify the oblique asymptote of #f(x) = (2x^2+3x+8)/(x+3)#?

##### 1 Answer

Mar 2, 2016

#### Answer:

Oblique Asymptote is

Vertical Asymptote is

#### Explanation:

from the given:

perform long division so that the result is

Notice the part of the quotient

equate this to

And the divisor

You can see the lines

graph{(y-(2x^2+3x+8)/(x+3))(y-2x+3)=0[-60,60,-30,30]}

God bless...I hope the explanation is useful..