How do you identify the vertical asymptotes of #f(x) = (10)/(x^2-7x-30)#?

1 Answer

Answer:

Well, as #x->-3# then #f (x) ->oo#
and as #x->10# then #f(x)->oo#

Explanation:

To get to this answer, you'll first have to factorize the denominator, to see when this gets (closer and closer) to zero.
#x^2-7x-30=(x+3)(x-10)#

Hence #x=-3, x=10# vertical asymptotes.

The graph for #f(x)# is

graph{10/(x^2-7x-30) [-20.27, 20.26, -10.14, 10.13]}