How do you identify the vertices, foci, and direction of #y^2/25-x^2/16=1#?
1 Answer
Nov 27, 2017
See the explanation below
Explanation:
The equation is
This is the equation of a hyperbola with a vertical transverse axis.
The center of the hyperbola is
The vertices are
The foci are
where
The foci are
The asymptotes are
The asymptotes are
graph{y^2/25-x^2/16=1 [-32.47, 32.47, -16.25, 16.24]}