# How do you identify the vertices, foci, and direction of #y^2/25-x^2/16=1#?

##### 1 Answer

Nov 27, 2017

See the explanation below

#### Explanation:

The equation is

This is the equation of a hyperbola with a vertical transverse axis.

The center of the hyperbola is

The vertices are

The foci are

where

The foci are

The asymptotes are

The asymptotes are

graph{y^2/25-x^2/16=1 [-32.47, 32.47, -16.25, 16.24]}