# How do you identity if the equation #2x^2+3x-4y+2=0# is a parabola, circle, ellipse, or hyperbola and how do you graph it?

##### 1 Answer

Feb 23, 2017

#### Answer:

The given equation is a Parabola.

#### Explanation:

Given -

#2x^2+3x-4y+2=0#

The general for of the conic equation can be written as

#Ax^2+Cy^2+Dx+Ey+F=0#

In such case -

If

In the given equation

The coefficeint of

In the given equation

To graph the equation, solve it for

#4y=2x^2+3x+2 #

#y=0.5x^2+0.75x+0.5#

Find its vertex

#x=(-b)/(2a)=(-0.75)/(2 xx 0.5)=-0.75#

Take a few points on either side of

Calculate the corresponding

Tabulate them

Plot the point on a graph sheet. connect them with a smooth curve.