# How do you implicitly differentiate #2=ytanx-xy #?

##### 1 Answer

Jan 3, 2016

#### Explanation:

Find the derivative of each part separately.

#d/dx(2)=0#

Next, use the product rule. Remember that when implicitly differentiating, the chain rule will kick in and spit out

#d/dx(ytanx)=y'tanx+ysec^2x#

Again, use the product rule.

#d/dx(-xy)=-y-xy'#

Combine all the derivatives and solve for