Question

How do you implicitly differentiate `(5+y)^(3)+2y=x+220`?

Answer 1

y' = `1/(3(5+y)^2+2)`

Explanation:

given: `(5+y)^3+2y = x + 220`
differentiate with respect to x on both sides of the equation.
obtaining `3(5+y)^2 * (0+y')+2y' = 1`
by simplification obtain `3(5+y)^2 *y' + 2y' = 1`
solve for y' to obtain `y'=1/(3(5+y)^2 + 2)`