# How do you implicitly differentiate (5+y)^(3)+2y=x+220?

y' = $\frac{1}{3 {\left(5 + y\right)}^{2} + 2}$
given: ${\left(5 + y\right)}^{3} + 2 y = x + 220$
obtaining $3 {\left(5 + y\right)}^{2} \cdot \left(0 + y '\right) + 2 y ' = 1$
by simplification obtain $3 {\left(5 + y\right)}^{2} \cdot y ' + 2 y ' = 1$
solve for y' to obtain $y ' = \frac{1}{3 {\left(5 + y\right)}^{2} + 2}$