Question

How do you implicitly differentiate `5y^2=e^(2x-4y)-3x`?

Answer 1

`dy/dx=(2e^(2x-4y)-3)/(10y+4e^(2x-4y))`

Explanation:

`5y^2=e^(2x-4y)-3x`

`10y dy/dx=2e^(2x-4y)-4e^(2x-4y)dy/dx-3`

`10y dy/dx+4e^(2x-4y)dy/dx=2e^(2x-4y)-3`

`dy/dx(10y+4e^(2x-4y))=2e^(2x-4y)-3`

`dy/dx=(2e^(2x-4y)-3)/(10y+4e^(2x-4y))`