Question

How do you implicitly differentiate `y^2-xy-6=0`?

Answer 1

You can do it like this:

Explanation:

`y^2-xy-6=0`

`:.D(y^2-xy-6)=D(0)`

`:.2yy'-(xy'+y)=0`

`:.2yy'-xy'-y=0`

`:.y'(2y-x)=y`

`y'=(y)/((2y-x))`