Question

How do you integrate `(cscx)^2`?

Answer 1

`intcsc^2xdx=-cotx+C`

Explanation:

This is actually a common integral.

Recall that `d/dxcotx=-csc^2x`

Then,

`d/dx(-cotx)=csc^2x`

So, since we differentiate `-cotx` to get `csc^2x`,

`intcsc^2xdx=-cotx+C`