Question

How do you integrate `(e^(2x-1))-1`?

Answer 1

`= 1/2e^(2x-1)- x + C`

Explanation:

`int \ (e^(2x-1))-1 \ dx`

`= int \ d/dx(1/2e^(2x-1))-1 \ dx`

`= 1/2e^(2x-1)- x + C`