Question

How do you integrate `g(t)=t^2-4/t` using the power rule?

Answer 1

The derivative of the function is `g'(t)=2t+4/t^2`

Explanation:

The power rule states that the derivative of `f(t)=t^n` is `f'(t)=nt^(n-1)`.

Rewrite the function with a negative exponent:

`g(t)=t^2-4t^-1`

Now apply the power rule:

`g'(t)=2t^(2-1)-4(-1)t^(-1-1)`

`g'(t)=2t^1+4t^-2`

`g'(t)=2t+4/t^2`