How do you integrate #int 1/sqrt(x^2-6) # using trigonometric substitution?
Given equation is
For this equation, we'll substitute
Substituting these values into the equation, we get
I believe you're well friends with this general trigonometric equation
Therefore, the denominator of the integral becomes
Now, we know that
Also, from the above trigonometric identity,
So substituting the above values for their respective functions, we get the integral of the said main function.