How do you integrate #int (3x)/sqrt((1-x^2))dx# using trigonometric substitution?
You need to use the beautiful Pythagorean right triangle.
Here is the general antiderivative :
Here's a quick paint job to show you the lovely right triangle:
You now need to find the following:
I'll give you a gentle and loving push in the right direction:
What is x?
Well, it sure looks to be :