Question

How do you integrate `int (5-e^x)/(e^(2x))dx`?

Answer 1

`-5/2e^(-2x)+e^-x+C`

Explanation:

rearrange as folows.

`int((5-e^x)/e^(2x))dx`

`=int(5/e^(2x)-e^x/e^(2x))dx`

`int(5e^(-2x)-e^(-x))dx`

`=-5/2e^(-2x)+e^-x+C`