Question

How do you integrate `int(5+lnx)^5/x` using substitution?

Answer 1

`(5+lnx)^5/6+C`

Explanation:

Let us take the subst. `(5+lnx)=t`, so that, `1/xdx=dt`

Hence, `int(5+lnx)^5/xdx=intt^5dt=t^6/6=(5+lnx)^6/6+C`