How do you integrate #int sin2x dx#?

1 Answer
Write your answer here...
Start with a one sentence answer
Then teach the underlying concepts
Don't copy without citing sources
preview
?

Answer

Write a one sentence answer...

Answer:

Explanation

Explain in detail...

Explanation:

I want someone to double check my answer

Describe your changes (optional) 200

71
sente Share
Dec 17, 2016

Answer:

#intsin(2x)dx=-1/2cos(2x)+C#

Explanation:

Using integration by substitution together with the known integral #intsin(x)dx = -cos(x)+C#, we first let #u = 2x => du = 2dx#. Then

#intsin(2x)dx = 1/2intsin(2x)2dx#

#=1/2intsin(u)du#

#=1/2(-cos(u))+C#

#=-1/2cos(2x)+C#

Was this helpful? Let the contributor know!
1500