How do you integrate #int (x^2-1)/((x-3)(x^2-1)(x+3)) dx# using partial fractions?
First cancel out the silly common factor
Then split the denominator, leaving gaps to be filled in:
Then use the cover-up rule of partial fractions to fill in the gaps:
and do the standard integrals:
and optionally re-arrange use the properties of logarithms
In the cover up rule, you put your finger over the
denominator. If you don't accept the standard integral of