Question

How do you integrate `int (x^2 - 4) / (x -1) dx` using partial fractions?

Answer 1

I wouldn't call it partial fractions, but you do the division to get:

Explanation:

`int (x^2-4)/(x-1) dx = int (x+1-3/(x-1)) dx`

`= 1/2x^2+x-3ln abs(x-1) +C`