Question

How do you integrate `(sinx+secx)/tanx`?

Answer 1

Rewrite
`int((sinx+1/cosx)/(sinx/cosx))dx`

`=int(((sinxcosx+1)/cancelcosx)/(sinx/cancelcosx))dx`

`=int(((cancelsinxcosx)/cancelsinx)+1/sinx)dx`

`=int(cosxdx)+int(cscxdx)`

Now both of these are standard integrals

`=sinx-ln(csc(x)+cot(x)) +`Constant