Question

How do you integrate `sqrt3sinx(cosx)^0.5`?

Answer 1

`intsqrt3 sin x (cos x)^0.5 dx=-(2sqrt3)/3( cos x )^1.5+C`.

Explanation:

The integral is `-sqrt3int(cos x)^0.5d(cos x)`
`=-sqrt3( cos x )^(0.5+1)/(0.5+1)+C`
`= -(2sqrt3)/3( cos x )^1.5+C`