# How do you integrate ((x^3 + 7) / x^2) dx?

$\int \left(\frac{{x}^{3} + 7}{x} ^ 2\right) \mathrm{dx} = \frac{{x}^{3} - 14}{2 x}$
$\int \left(\frac{{x}^{3} + 7}{x} ^ 2\right) \mathrm{dx} = \int \left({x}^{3} / {x}^{2} + \frac{7}{x} ^ 2\right) \mathrm{dx} = \int x \mathrm{dx} + 7 \int {x}^{- 2} \mathrm{dx}$
$= {x}^{2} / 2 - 7 {x}^{-} 1 = {x}^{2} / 2 - \frac{7}{x} = \frac{{x}^{3} - 14}{2 x}$