Question

How do you integrate `y=3 (5x+9)^9`?

Answer 1

Do a "u" substitution. Please see the explanation.

Explanation:

Let `u = 5x + 9`, then `du = 5dx, dx = 1/5du`

`int3(5x + 9)^9dx = 3/5intu^9du`

`int3(5x + 9)^9dx = 3/50u^10 + C`

Reverse the substitution:

`int3(5x + 9)^9dx = 3/50(5x + 9)^10 + C`