How do you long divide $n^{2} - 11 n - 26$ $n^2 - 11n - 26$ by $n + 2$ $n+2$ ?

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How do you long divide $n^{2} - 11 n - 26$ $n^2 - 11n - 26$ by $n + 2$ $n+2$ ?

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Answer 1 · 2015-10-20T17:42:24

$n - 13$ $n-13$

Explanation:

I'll just show you my solution here.

$" "ul(n-13)$
$n+2" "|n^2-11n-26$
$color(white)(n+2)" "ul(-n^2-2n)$
$color(white)(n+2)" "-13n-26$
$color(white)(n+2)" "ul(13n+26)$
$color(white)(n+2)" "0$

So, $n^2-11n-26$ divided by $n+2$ is $color(blue)(n-13)$ .

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How do you long divide $n^{2} - 11 n - 26$ $n^2 - 11n - 26$ by $n + 2$ $n+2$ ?

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How do you long divide n^2 - 11n - 26n2−11n−26n^2 - 11n - 26 by n+2n+2n+2?

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How do you long divide $n^{2} - 11 n - 26$ $n^2 - 11n - 26$ by $n + 2$ $n+2$ ?