# How do you long divide (x^2 + 6x +5)/(x^2-3x-4)?

$\frac{x + 5}{x - 4}$
$\frac{{x}^{2} + 6 x + 5}{{x}^{2} - 3 x - 4} = \frac{\cancel{\left(x + 1\right)} \left(x + 5\right)}{\cancel{\left(x + 1\right)} \left(x - 4\right)}$