Question

How do you minimize and maximize `f(x,y)=x^2+y^(3/2)` constrained to `0<x+3y<2`?

Answer 1

For the minimum, set `y=0` and then pick a value for x as close to 0 as you like.

For the maximum, set `y = 0` and then pick a value for x as close to 2 as you like.