How do you multiply #1/2 (2n - 4) - 2n#?

1 Answer
Jul 30, 2016

-n-2

Explanation:

not sure if you meant 'simplify' here as the string has limited multiplication.

use order of operations here by multiplying #(2n - 4)# by #1/2# which gives you #((2n)/2 - 4/2)#. when you do the division, you are left with #n - 2#. remove the brackets and group like terms:

#n - 2 - 2n#
#x = -n - 2#