# How do you multiply (1/(m^2-m)) + (1/m)=5/(m^2-m)?

Apr 11, 2018

$m = 5$

#### Explanation:

the common denominator between ${m}^{2} - m$ and $m$ would be ${m}^{2} - m$, since ${m}^{2} - m$ is a multiple of $m$.

${m}^{2} - m = m \left(m - 1\right)$

$\frac{1}{m} = \frac{1 \left(m - 1\right)}{m \left(m - 1\right)}$

$= \frac{m - 1}{{m}^{2} - m}$

$\frac{1}{{m}^{2} - m} + \frac{m - 1}{{m}^{2} - m} = \frac{1 + m - 1}{{m}^{2} - m}$

$= \frac{m}{{m}^{2} - m}$

$\frac{m}{{m}^{2} - m} = \frac{5}{{m}^{2} - m}$

hence, $m = 5$