How do you multiply #(1/(r-2)) + (1/(r^2-7r+10))=6/(r-2)#?
In order to sum (and not multiply) the first two fractions, we must find the lowest common denominator among them. In order to simplify things for us, we can factor the second denominator, finding its roots, as follows:
Rewriting these roots, we can say that
Rewriting your sum, we get
Now, we have the equation
Cross multiplying them, we get