How do you multiply #2(6+10)#?

1 Answer
May 8, 2016

Answer:

32

Explanation:

#color(blue)("Shortcut method")#

#2xx16=32#

'~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Teaching bit:")#

suppose you had #2(a+b)#

This is 2 lots of #(a+b)#

So #2(a+b)" "->" "(a+b)+(a+b)#

Which is: #a+a+b+b = 2a+2b#

From this you can observe that you get the same answer if you just multiply everything inside the brackets by 2.

Suppose you had #=-3(a+b) = -3a-3b#

Suppose you had #-3(a-4b) = -3a+12b#

Suppose you had #5(1/(5a)+b/10) =5/(5a)+(5b)/10= 1/a+b/2#