How do you multiply #(2x+3v)^2#?

1 Answer
Feb 11, 2017

See the entire solution process below.

Explanation:

We can rewrite this express as:

#(2x + 3v)(2x + 3v)#

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(2x) + color(red)(3v))(color(blue)(2x) + color(blue)(3v))# becomes:

#(color(red)(2x) xx color(blue)(2x)) + (color(red)(2x) xx color(blue)(3v)) + (color(red)(3v) xx color(blue)(2x)) + (color(red)(3v) xx color(blue)(3v))#

#4x^2 + 6xv + 6xv + 9v^2#

We can now combine like terms:

#4x^2 + (6 + 6)xv + 9v^2#

#4x^2 + 12xv + 9v^2#